Respuesta :

Answer:

I think the answer is D.

Step-by-step explanation:

[tex] \frac{ {5y}^{3} }{ {(5y)}^{ - 2} } \\ = \frac{ {5y}^{3} }{ {(\frac{1}{5y})}^{2} } \\ = {5y}^{3} \times {25y}^{2} \\ = 125 {y}^{5} [/tex]

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