Answer:
65 °C
Explanation:
Step 1: Given data
- Initial temperature (Ti): 25 °C
- Specific heat of water (c): 4.184 J/g.°C
Step 2: Calculate the final temperature (T)
We will use the following expression.
Q = c × m × ΔT
T = Q / c × m + Ti
T = 832 J / (4.184 J/g.°C) × 5.0 g + 25 °C
T = 65 °C
