Answer:
Explanation:
gold sulfide = 15.267 g
gold = 12.272 g
sulphur = 15.267 - 12.272 = 2.995 g
moles of gold = 12.272 / 196.96 = .0623 moles
moles of sulphur = 2.995 / 32 = .0936 moles
ratio of moles of gold and sulphur in the compound = .0623 : .0936
= 2 : 3
empirical formula Au₂S₃
