Answer:
[tex]Q=5941.3J[/tex]
Explanation:
Hello.
In this case, since the water is absorbing heat because its temperature raises from 30.2 °C to 58.6 °C, we can compute the amount of heat shown below:
[tex]Q=mCp\Delta T[/tex]
Whereas the specific heat of water is known to 4.184 J/(g°C), thus, we obtain:
[tex]Q=50.0g*4.184\frac{J}{g\°C}(58.6-30.2)\°C \\\\Q=5941.3J[/tex]
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