anae223 anae223

25-09-2020
Mathematics

contestada

If HJ=2x+5, JK=3x-7, and KH=18 what is the value of x

Respuesta :

mhanifa mhanifa

25-09-2020

Answer:

x = 4

Step-by-step explanation:

Given

HJ=2x+5
JK=3x-7
KH=18

We see J is between H and K, so

KH = HJ + JK
2x + 5 + 3x - 7 = 18
5x - 2 = 18
5x = 20
x = 4

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