kaleighmorr7
kaleighmorr7 kaleighmorr7
  • 26-08-2020
  • Mathematics
contestada

10[6(n+1)+5(n-1)]=13[7(5+n)-(25-3n)]

Respuesta :

renee405 renee405
  • 26-08-2020

Answer:

n = -6

Step-by-step explanation:

10[6(n+1)+5(n-1)]=13[7(5+n)-(25-3)]

You will collect like terms

10(6n+6+5n-5)=13(35+7n-25+3)

it will give you this

10(11n+1)=13(10+10n)

Then you remove the parenthesis

110n+10 = 130 +130n

Move the terms

110n -130n = 130-10

collect like terms

-20n=120

divide both sides

n=-6

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