Answer:
[tex](\sqrt{x} -8)^{4}+6[/tex]
Step-by-step explanation:
[i assume by 9(x) , you meant g(x)]
we start from the inner one, h(x):
[tex]h(x)=\sqrt{x}[/tex]
now to the g(h(x):
[tex]g(h(x))=g(\sqrt{x} )=\sqrt{x} -8[/tex]
now to the f:
[tex]f(\sqrt{x} -8)=(\sqrt{x} -8)^{4}+6[/tex]
