avatalisavazquez avatalisavazquez
  • 25-06-2020
  • Mathematics
contestada

Find The equation of a circle that has it center at (-4,3) and has a radius of 5.

Find The equation of a circle that has it center at 43 and has a radius of 5 class=

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ujalakhan18
ujalakhan18 ujalakhan18
  • 25-06-2020

Answer:

A.

Step-by-step explanation:

Center = (a,b) = (-4,3)

So, a = -4, b = 3

Radius = 5

Equation of circle:

[tex](x-a)^2+(y-b)^2 = r^2[/tex]

Putting the givens

=> (x+4)²+(y-3)² = 25

Answer Link
ZJSG09112007
ZJSG09112007 ZJSG09112007
  • 25-06-2020

[tex] {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\

{(x - (4))}^{2} + {(y + 3))}^{3} = {5}^{2} \\ {(x - 4)}^{2} + {(y + 3)}^{2} = 25[/tex]

Ver imagen ZJSG09112007
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