Harpreet83 Harpreet83
  • 24-06-2020
  • Mathematics
contestada

(Squreroot x+2)(squreoot x-2)=0

Respuesta :

Alfpfeu
Alfpfeu Alfpfeu
  • 24-06-2020

Answer:

[tex]\boxed{ \ x = 2 \ or \ x = -2 \ }[/tex]

Step-by-step explanation:

I understand that you want to solve this equation

[tex]\sqrt{x+2}\sqrt{x-2}=0[/tex]

<=>

[tex]\sqrt{(x+2)(x-2)}=0[/tex]

<=>

[tex](x+2)(x-2)=0[/tex]

<=>

x = 2 or x = -2

hope this helps

if your question is [tex](\sqrt{x}+2)(\sqrt{x}-2) = 0[/tex]

then this is [tex](\sqrt{x})^2-4 = 0\\<=> x = 4[/tex]

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