Answer:
see explanation
Step-by-step explanation:
Given
[tex]\sqrt{\frac{4x^2}{3y} }[/tex]
= [tex]\frac{\sqrt{4x^2} }{\sqrt{3y} }[/tex]
= [tex]\frac{2x}{\sqrt{3y} }[/tex]
Rationalise the denominator by multiplying the numerator/ denominator by [tex]\sqrt{3y}[/tex]
Note that [tex]\sqrt{a}[/tex] × [tex]\sqrt{a}[/tex] = a
= [tex]\frac{2x}{\sqrt{3y} }[/tex] × [tex]\frac{\sqrt{3y} }{\sqrt{3y} }[/tex]
= [tex]\frac{2x\sqrt{3y} }{3y}[/tex]
