jay9spam jay9spam
  • 21-06-2020
  • Mathematics
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What is the equation of the line perpendicular to y = 2/3x+1that passes through the point (12, -6)?

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GeorgePP
GeorgePP GeorgePP
  • 21-06-2020

Answer:[tex]y=-\frac{3}{2} x+12[/tex]

Step-by-step explanation:

Perpendicular lines have inversely proportional slopes. So make the slope negative and switch it to its reciprocal.

2/3x would change into -3/2x

Lets write that down for a starting point for our perpendicular line.

y = -3/2x + b

We were given the x and y value via the coords. x = 12 and y = -6

Now we have -6 = -3/2(12) + b. Multiply -3 and 12 to get -36, then divide by 2 to get -18.  Now it's -6 = -18 + b. Solve for b by adding 18 to both sides to get b = 12

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