genevariggs5
genevariggs5 genevariggs5
  • 26-05-2020
  • Mathematics
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(x +8/3)2 +y2=1
what is it's center
(. ,. )
what is it's radius​

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santiagochile7777 santiagochile7777
  • 26-05-2020

Answer: Center is [tex](-\frac{8}{3}, 0)[/tex] and radius is 1.

Step-by-step explanation: The center of a circle [tex](x-a)^{2} + (y-b)^{2} = r^{2}[/tex] is (a,b) & the radius is r. a=[tex]--\frac{8}{3} = \frac{8}{3}[/tex] , b=0, and r=[tex]\sqrt{1}[/tex]=1

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