Answer:
(2g + 1)(5g + 2)
Step-by-step explanation:
Given
10g² + 9g + 2
Consider the factors of the product of the g² term and the constant term which sum to give the coefficient of the g- term.
product = 10 × 2 = 20 and sum = 9
The factors are + 5 and + 4
Use these factors to split the g- term
10g² + 5g + 4g + 2 ( factor the first/second and third/fourth terms )
= 5g(2g + 1) + 2(2g + 1) ← factor out (2g + 1) from each term
= (2g + 1)(5g + 2) ← in factored form
