madisont82 madisont82
  • 25-05-2020
  • Mathematics
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Factor the tribunal into two binomials than solve?

Factor the tribunal into two binomials than solve class=

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mirai123
mirai123 mirai123
  • 25-05-2020

Answer:

[tex](x-5)(x-3)=0[/tex]

[tex]x=5 \text{ and } x=3[/tex]

Step-by-step explanation:

Quadratic Equation given:

[tex]x^2-8x+15=0[/tex]

In order to factor this equation think that we'll have something in the format:[tex](x-a)(x-b)[/tex]

Once: -a -b = -c

and (-a)(-b)= d

Therefore, we have

[tex](x-5)(x-3)=0[/tex]

[tex]x-5=0\\\text{or}\\x-3=0[/tex]

[tex]x=5 \text{ and } x=3[/tex]

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