Answer:
64^(a+b)= 32^(a+2b)
<=>(2^6)^(a+b) = (2^5)^(a+2b)
<=>2^(6a+6b) = 2^(5a+10b)
=> 6a + 6b = 5a + 10b
=> a = 4b
Hope this helps!
:)
