Answer:
Step-by-step explanation:
The sum of the coefficients in the expansion of (x+1)^12:
= 12C0 + 12C1 + 12C2 + . . . + 12C11 + 12C12
the formula says that this sum equal to 2¹².
Other examples
The sum of the coefficients in the expansion of (x+1)^3:
3C0+3C1+3C2+3C3
=8 = 2³
The sum of the coefficients in the expansion of (x+1)^4:
4C0+4C1+4C2+4C3+4C4
=16 = 2⁴
:)
