Answer:
7
Step-by-step explanation:
Replace the variations with given values: z = 9 and y = 6
[tex] \frac{ {z}^{2} - 3y }{z} \\ \frac{ {9}^{2} - 3 \times 6 }{9} = \frac{81 - 18} {9} \\ \frac{63}{9} = 7[/tex]
substitute the variables
[tex]\frac{9^{2}-3(6) }{9}[/tex]
[tex]\frac{81-18}{9}[/tex]
[tex]\frac{63}{9}[/tex]
= 7
