bascolocanela bascolocanela
  • 23-04-2020
  • Chemistry
contestada

How many moles of KMnO, are in 66.38 g of KMnO?

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znk
znk znk
  • 05-05-2020

Answer:

[tex]\large \boxed{\text{0.4200 mol}}[/tex]

Explanation:

[tex]\text{M$_{r}$ of KMnO$_{4}$} = 158.03\\\text{Moles} = \text{66.38 g } \times \dfrac{\text{1 mol}}{\text{158.03 g}} = \text{0.4200 mol}\\\\\rm \text{The sample contains $\large \boxed{\textbf{0.4200 mol}}$ of KMnO$_{4}$}[/tex]

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