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  • 22-04-2020
  • Mathematics
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306flower
306flower 306flower
  • 22-04-2020

Say Louis addresses x envelopes in some amount of time. In that time, Jane, addressing twice as many, will have addressed 2x envelopes. Total, they'll address 240 envelopes. So, we can add the x and 2x to solve for x.

x + 2x = 240

3x = 240

x = 80

If Louis addresses x envelopes and x = 80, Louis will address 80 envelopes. If Jane addresses twice as many, you do 80 * 2, getting 160 envelopes.

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