sarweston1867 sarweston1867
  • 22-04-2020
  • Mathematics
contestada

Find a in a geometric series for which Sn = 728, r = 3 , and n = 6.

Respuesta :

AFOKE88 AFOKE88
  • 25-04-2020

Answer:

a = 2

Step-by-step explanation:

In geometric series, Sum of the series formula :

Sn = a[(rⁿ - 1)/(r - 1)]

We are given that Sn = 728 and

r = 3 and n =6

Thus,plugging in the relevant values;

728 = a[(3^(6) - 1)/(3 - 1)]

728 = 364a

a = 728/364

a = 2

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