taylordabney23 taylordabney23

22-04-2020
Mathematics

contestada

Which quadratic equation defines the function that has zeros at -8 and 6?
A. x^2 + 2x - 48 = 0
B. x^2 - 2x - 48 = 0
C. x^2 + 2x + 48 = 0
D. x^2 - 2x + 48 = 0

Respuesta :

jadkain62 jadkain62

22-04-2020

Answer: it is A

Step-by-step explanation:

x^2+2x-48=0

x^2+8x-6x-48=0

x×(x+8)-6(x+8)=0

(x+8)×(x-6)=0

x+8=0

x-6=0

x=-8

x=6

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