Answer:
[tex]Volume=\frac{2}{3} \, \pi \,x^3[/tex] which agrees with the first answer listed among your options
Step-by-step explanation:
Volume of cone: [tex]\frac{1}{3} Base\,*\,height[/tex]
So in our case:
1) Base s a circle, of radius "x" then the surface of this is: [tex]Area = \pi \,r^2 =\pi\,x^2[/tex]
2) the cone's height is "2x"
Therefore the cone's volume is: [tex]Volume=\frac{1}{3} \pi x^2\,(2x)=\frac{2}{3} \, \pi \,x^3[/tex]
