The equation is already in standard form [ ax² + bx + c = y ] so we can find the values of each variable.
a = 1
b = 10
c = 3
y = 0
Quadratic formula: [tex]x = \frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
Solve using the formula:
[tex]x=\frac{-10+-\sqrt{10^2-4(1)(3)} }{2(1)}[/tex]
[tex]x=\frac{-10+-\sqrt{100 - 12} }{2}[/tex]
[tex]x=\frac{-10+-\sqrt{88} }{2}[/tex]
[tex]x=-5+-\sqrt{22}[/tex]
Therefore, the answer is [ x = -5 ± √22 ]
Best of Luck!
