Answer:
Explanation:
Given component reaction as this
2H2(g)+O2(g)--------2H2O. ∆H =-
483.6kj----1
3O2(g)------2O3(g). ∆H= +284.6kj.---2
Calculating the o eral ethalpy for
3H2(g)+03(g)----3H2O(g)----3
Equation 3 can be found as this
3(1)-eqn 2/3
-3*483.6-284.6/2=-867.7kj
