prettekenniather
prettekenniather prettekenniather
  • 21-07-2016
  • Mathematics
contestada

Find the 7th partial sum of (infinit) over E and under E is i=1, then the equation on the right side of E is 6(3)^(i-1).
*the E is the sigma notation symbol*
please help

Respuesta :

Vinmary Vinmary
  • 21-07-2016
since i=1, 
6(3)^i-1
6(3)^1-1
6(3)^0
6(1)
=6.
:- 6(3)^i-1 = 6
Answer Link
meerkat18
meerkat18 meerkat18
  • 22-07-2016
The partial sum can be determined through the calculator or substituting the value to the variable manually. 

6(3)^(1-1) = 6
6(3)^(2-1) = 18
6(3)^(3-1) = 54  
6(3)^(4-1) = 162 
6(3)^(5-1) = 486
6(3)^(6-1) = 1458
6(3)^(7-1) = 4374

total is  
 6558
Answer Link

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