majedomran1425 majedomran1425
  • 26-03-2020
  • Mathematics
contestada

For a triangle ABC, with AB=4, AC=7 and BAC^=30°, find the remaining angles.

Respuesta :

kenlingdad kenlingdad
  • 26-03-2020

Answer:

29° , 121°       or ≈ 30° and ≈ 120°

Step-by-step explanation:

Law of cosine: a² = b² + c² -2bc cos A

a² = 16 + 49 - 2 x 4 x 7 x cos30° = 16.5

a = 4.1

Law of sin: smaller angle   4 / sin ∠BCA = 4.1 / sin 30°

sin ∠BCA = 0.49

∠BCA = 29°    (≈30°)

∠ABC = 180 - 29 - 30 = 121°    (≈120°)

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