[tex](sin x - cos x)^{2} = 1 - 2 sin x cos x[/tex]
Step-by-step explanation:
Step 1 : Taking L.H.S(Left Hand Side) we have,
[tex](sin x - cos x)^{2} = sin^{2} x + cos^{2} x - 2 sin x cos x[/tex] ... equation (1)
Step 2 : As we know, [tex]sin^{2} x + cos^{2} x = 1[/tex]
Therefore,
by substituting value in equation (1), we have
[tex]1 - 2 sin x cos x[/tex]
Step 3 : As, L.H.S = R.H.S
Hence Proved,
[tex](sin x - cos x)^{2} = 1 - 2 sin x cos x[/tex]
