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23-03-2020
Mathematics

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How many solutions for linear equation 3x + 5y = 25 can be found so that −20 < y < 10, and x is an integer?

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amna04352 amna04352

23-03-2020

Answer:

50

Step-by-step explanation:

3x = 25 - 5y

-100 < 5y < 50

-50 < -5y < 100

-25 < 25 - 5y < 125

-8.333 < x < 41.667

41+8+1 = 50

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