brokenheart1
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  • 23-03-2020
  • Mathematics
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Please Help! Geometry!

Please Help Geometry class=

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Wallind11
Wallind11 Wallind11
  • 23-03-2020

Step-by-step explanation:

Suppose AB is the 3- foot high access ramp that ends at point C 20 feet along the ground and

theta is the angle of depression from the start of 3 foot high ramp at point A

Now, in ∆ ABC

m<ACB= theta ( alternate interior angle)

Therefore,

[tex] \tan(theta) = \frac{AB}{BC} [/tex]

[tex] \tan(theta) = \frac{3}{20} [/tex]

(theta) = tan⁻¹(3/20)

= 8.5°

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