tris2002 tris2002
  • 23-03-2020
  • Mathematics
contestada

(6-i)/(4+3i) what is the quotient?

Respuesta :

MikeMart77
MikeMart77 MikeMart77
  • 23-03-2020

Answer:

[tex]\frac{21}{25} - \frac{22}{25} i[/tex]

Step-by-step explanation:

[tex] \frac{6 - i}{4 + 3i} = \\ = \frac{(6 - i)(4 - 3i)}{(4 + 3i)(4 - 3i)} = \\ = \frac{24 - 18i - 4i + 3{i}^{2} }{16 - 12i + 12i - 9 {i}^{2} } = \\ = \frac{24 - 18i - 4i + 3( - 1)}{16 - 9( - 1)} = \\ = \frac{24 - 22i - 3}{16 + 9} = \\ = \frac{21 - 22i}{25} = \\ = \frac{21}{25} - \frac{22}{25} i[/tex]

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