Answer: Our solutions are x= -7 or x = 6.
Step-by-step explanation:
Since we have given that
[tex]x^2+x-30=12[/tex]
We need to find the solutions to the above equations:
First we calculate the constants:
[tex]x^2+x-30=12\\\\x^2+x-30-12=0\\\\x^2+x-42=0[/tex]
Now, we will split the middle term:
[tex]x^2+x-42=0\\\\x^2+7x-6x-42=0\\\\x(x+7)-6(x-7)=0\\\\(x+7)(x-6)=0[/tex]
As we know that
a.b=0
⇒either a = 0 or b = 0
[tex](x+7)=0\ or\ (x-6)=0\\\\x=-7,6[/tex]
So, our solutions are x= -7 or x = 6.
