Gracie6add0ymeisri
Gracie6add0ymeisri Gracie6add0ymeisri
  • 23-06-2016
  • Mathematics
contestada

Solve. open parentheses square root of 7 close parentheses to the 6 x power = 49x-6

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Аноним Аноним
  • 07-07-2016
Is this the equation?
[tex] (\sqrt{7^}}) ^6x} = 49 ^{x-6} [/tex]

First is to transform the two sides of the equation to have like bases.
[tex]7^{ \frac{6x}{2} } = 7^{2(x-6)}[/tex]

Simplifying would result to:
[tex] 7^{3x}} = 7^{2x-12} [/tex]

Equating the exponents:
3x =2x+12
x= 12

If you would want to solve for x then x=12.
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snipper2188
snipper2188 snipper2188
  • 04-02-2021

Answer:

For flvs students the answer is  x = -12

Step-by-step explanation:

I just took the test

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