Respuesta :

animemauluna

sinФ = 1/6

sinФ = opposite/hypotenuse

cosФ = adjacent/hypotenuse

tanФ = opposite/adjacent

SOHCAHTOA

1^(2)+b^(2)=6^(2)

1+b^(2)=36

b^(2)=35

[tex]\sqrt{35}[/tex]

cosФ = [tex]\sqrt{35}[/tex]/6

tanФ = 1/[tex]\sqrt{35}[/tex] = [tex]\sqrt{35}[/tex]/35

Officialalehpeter

Answer:

Cos ø = √35/6

Tan ø = √35/35

Step-by-step explanation:

Sin ø = opposite/hypothenus

Sin ø = 1/6

Pythagoras theorem says

Hyp² = Opp² + Adj²

6² = 1² + A²

A² = 35

A = √35

Hence, cos ø = √35/6

tan ø = 1/√35 = √35/35

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