haydenallen681 haydenallen681
  • 25-01-2020
  • Mathematics
contestada

Dimensions of a rectangle whose length is 8 more than twice it’s width and has a perimeter of 40 cm.

Respuesta :

nkirotedoreen46
nkirotedoreen46 nkirotedoreen46
  • 31-01-2020

Answer:

Width = 4 cm

Length = 16 cm

Step-by-step explanation:

We are given;

  • Perimeter = 40 cm
  • Assuming the width is x
  • Then, length is 2x + 8 ( 8 more than twice the width)

We are required to determine the dimensions of the rectangle;

  • We need to know that the perimeter of the rectangle is given by;
  • Perimeter = 2 (length + width)

In this case;

2 ( 2x + 8 + x) = 40

2 ( 3x + 8 ) = 40

6x + 16 = 40

6x = 24

 x  = 4

Thus; the dimensions of the rectangle are;

Width = 4 cm, and

Length = 16 cm

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