Answer:
[tex]c\leq -32[/tex]
Step-by-step explanation:
Let
c ---> the number
we know that
The number c plus 6 must be less than or equal to -26
so
The inequality that represent this situation is
[tex]c+6\leq -26[/tex]
Solve for c
Subtract 6 both sides
[tex]c\leq -26-6[/tex]
[tex]c\leq -32[/tex]
The solution for c is the interval (-∞,-32]
All real numbers less than or equal to -32
In a number line, the solution is the shaded area at left of c=-32 (closed circle)
see the attached figure to better understand the problem
