Answer:
We need 25.3 mL of KOH
Explanation:
Step 1: Data given
Mass of potassium hydroxide (KOH) = 0.0284 grams
Molarity of KOH = 0.0200 M
Molar mass of KOH = 56.106 g/mol
Step 2: Calculate moles of KOH
Moles KOH = mass KOH / molar mass KOH
Moles KOH = 0.0284 grams / 56.106 g/mol
Moles KOH = 5.06 *10^-4 moles
Step 3: Calculate volume needed
Molarity KOH solution = moles KOH /volume
Volume = moles KOH / molarity KOH
Volume = 5.06 * 10^-4 moles / 0.0200 M
Volume = 0.0253 L = 25.3 mL
We need 25.3 mL of KOH
