Answer:
OH⁻ = 1.05×10⁻¹³ M
Explanation:
Given data;
H₃O⁺ = 9.61×10⁻² M
OH⁻ = ?
Solution:
First of all we will calculate the pH.
pH = -log [H⁺]
pH = -log [H₃O⁺]
Because pH is also the hydronium ion concentration.
pH = -log [ 9.61×10⁻²]
pH = 1.02
It is known that,
pH + pOH = 14
1.02 + pOH = 14
pOH = 14 - 1.02
pOH = 12.98
Concentration of OH⁻.
pOH = -log [OH⁻]
12.98 = -log [OH⁻]
OH⁻ = 10∧-12.98
OH⁻ = 1.05×10⁻¹³ M
