okendall
okendall okendall
  • 22-01-2020
  • Mathematics
contestada

2. Confirm that 1 + V5 and 1 - V5 are the correct roots for x^2 - 2x - 4 = 0.

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Kuroi
Kuroi Kuroi
  • 22-01-2020

Answer:

Step-by-step explanation:

[tex]{\displaystyle \Delta =b^{2}-4ac} (for this equation b=-2 ; a=1 ; c=-4 )

Δ= (-2)^2-4*(-4)*1=4+16=20

\sqrt{20} =2\sqrt{5}

x_{1}=\frac{2+2\sqrt{5} }{2} = \frac{2(1+\sqrt{5)} }{2} =1+\sqrt{5

x_{2}=\frac{2-2\sqrt{5} }{2} = \frac{2(1-\sqrt{5)} }{2} =1-\sqrt{5 [/tex]

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