madelynnpizzonia0129 madelynnpizzonia0129
  • 22-01-2020
  • Mathematics
contestada

Solve for x: 10^(2+logx) =21

Respuesta :

krjohnson03
krjohnson03 krjohnson03
  • 22-01-2020

Answer:

Step-by-step explanation:

Determine the defined range

Take the logarithm of both sides of the equation

Convert the constant into a logarithmic with base 10

Using loga(x)+ loga(y)=loga(xxy)

Evaluate the power

Since the base is based of the logarithmic are the same , set the argument equal

Divide both sides of the equation by 100

Check if the solution is in defined range

Answer: 21/100

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