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22-11-2019
Mathematics

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what is the standard form of y=-(x-2)(x-3)(x-2)?

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Yang100 Yang100

22-11-2019

Answer:

y=-x^3+7x^2-16x+12

Step-by-step explanation:

y=-(x-2)(x-3)(x-2)

y=-(x^2-2x-3x+6)(x-2)

y=-(x^2-5x+6)(x-2)

y=-(x^3-5x^2+6x-2x^2+10x-12)

y=-(x^3-7x^2+16x-12)

y=-x^3+7x^2-16x+12

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