Answer:
There are 0.0528 moles of Chromium Carbonate (III) in 15 grams. See the explanation below, please.
Explanation:
We calculate the weight of 1 mol of compound having the atomic weights of each element.
Weight Cr = 51, 9961 g Weight 0 = 15, 999 Weight C =12, 0107
Weight of 1 mol of Cr2 (C03)3 =51, 9961 x2 + 3 x (12, 0107 + 15, 999x 3)=
284, 0342 g
284, 0342 g -----1 mol of Cr2 (C03)3
15 g -----X = (15g x 1 mol)/284, 0342 g = 0, 0528 mol
