tsehaineshkidane230 tsehaineshkidane230
  • 25-10-2019
  • Chemistry
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How many Moles of NAOH are present in 2.50L of 0.300 M NaOH?

Respuesta :

nkirotedoreen46
nkirotedoreen46 nkirotedoreen46
  • 25-10-2019

Answer:

0.75 moles NaOH

Explanation:

We are given;

Volume of NaOH solution = 2.5 Liters

Molarity of NaOH = 0.300 M

We are required to calculate the moles of NaOH

We need to establish the relationship between moles, molarity and volume of a solution.

That would be;

Concentration/molarity = Moles ÷ Volume

Therefore;

Moles = Concentration × Volume

Thus;

Moles of NaOH = 0.300 moles × 2.50 L

                         = 0.75 moles

Therefore, the number of moles of NaOH is 0.75 moles

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