[tex]\frac{3a^{2}-13a+4 }{9a^{2} -6a+1}[/tex]*[tex]\frac{28+7a}{a^{2}-16 }[/tex]
[tex]\frac{(a-12)(a-1) }{(3a-1)^{2} }[/tex]*[tex]\frac{7(4+a)}{(a+4)(a-4)}[/tex]
[tex]\frac{(a-12)(a-1) }{(3a-1)^{2} }[/tex]*[tex]\frac{7}{(a-4)}[/tex]
result = [tex]\frac{(a-12)(a-1)7}{(3a-1)^{2}(a-4)}
Not sure about this
Let a vote and/or a thank if you like it!
