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A hammer is accidentally dropped from a scaffold where a crew is working. It takes the hammer 2.5 s to hit the ground. How high is the scaffold?

Respuesta :

MathPhys

Answer:

30.6 m

Explanation:

Given:

v₀ = 0 m/s

t = 2.5 s

a = 9.8 m/s²

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (2.5 s) + ½ (9.8 m/s²) (2.5 s)²

Δy ≈ 30.6 m