dulvedalvarez5077 dulvedalvarez5077
  • 21-10-2019
  • Mathematics
contestada

How are these two equations related? (x^2-1)/(x+1)= x-1 and x^2-1=(x+1)(x-1)

Respuesta :

aristeus aristeus
  • 24-10-2019

Answer:

These two equations are related to each other by identity [tex]a^2-b^2=(a+b)(a-b)[/tex]  

Step-by-step explanation:

We have given equations

[tex]\frac{x^2-1}{x+1}[/tex]

We know the algebraic identity

[tex]a^2-b^2=(a+b)(a-b)[/tex]

So [tex]a^2-1^2=(x+1)(x-1)[/tex]

So [tex]\frac{x^2-1}{x+1}=\frac{(x+1)(x-1)}{x+1}=(x-1)[/tex]

So these two equations are related to each other by algebraic identity [tex]a^2-b^2=(a+b)(a-b)[/tex]

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