Respuesta :

halo3blake
Moles CO = 10.0 g / 28.01 g/mol = 0.357 
the ratio between CO and CO2 is 2 : 2 ( or 1 : 1) so we would get 0.357 mole of CO2 ( 100% yield) 

mass CO2 = 0.357 mol x 44.0098 g/mol = 15.7 g ( theoretical yield) 

% yield = 12.8 x 100 / 15.7 = 81.5

Hope this helps.
TheOneAndOnlyKibeye
The % yield is 81.5 :DDDDDD

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