For this case we have the following system of equations:
[tex]2x-y = 7\\x-y = 0[/tex]
From the second equation we have:
[tex]x = y[/tex]
Substituting in the first equation:
[tex]2x-x = 7\\x = 7[/tex]
Now we find the value of "and":
[tex]x = y\\7 = y[/tex]
Then, the system solution is:
[tex](x, y) :( 7,7)[/tex]
Answer:
[tex](x, y) :( 7,7)[/tex]
