kmcb19 kmcb19
  • 26-07-2019
  • Mathematics
contestada

evaluate sin(Tan^-10)

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LammettHash
LammettHash LammettHash
  • 26-07-2019

[tex]\tan x=0[/tex] for [tex]x=n\pi[/tex], where [tex]n[/tex] is any integer. The inverse tangent function returns numbers between [tex]-\dfrac\pi2[/tex] and [tex]\dfrac\pi2[/tex]. The only multiple of [tex]\pi[/tex] in this range is 0, so [tex]\tan^{-1}0=0[/tex].

Then

[tex]\sin\left(\tan^{-1}0\right)=\sin0=\boxed0[/tex]

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