Answer:
-6x - 8y + 20 = 0
Step-by-step explanation:
If you have two points (x₁; y₁) and (x₂; y₂), you can use the formula to find the equation of a straight line:
[tex]\tt\boxed{\tt(y_1-y_2)x+(x_2-x_1)y+(x_1y_2-x_2y_1)=0}\\\\ \text{in your case:} \ x_1=6; \ x_2=-2; \ y_1=-2; \ y_2=4, \ \ so:\\\\(-2-4)x+(-2-6)y+(6\cdot4-(-2)(-2))=0\\\\-6x-8y+(24-4)=0\\\\-6x-8y+20=0[/tex]
