ANSWER
[tex](2x-7)(3x+4)[/tex]
EXPLANATION
The given expression is:
[tex] 6{x}^{2} - 13x - 28[/tex]
We find ac=6×-28=-168
Two factors of -168 that, if added will give us -13 are 8 and -21
We split the middle term to obtain,
[tex]6{x}^{2} + 8x - 21x- 28[/tex]
We now factor by grouping to obtain:
[tex]2x(3x + 4) - 7(3x + 4)[/tex]
Factor further to obtain;
[tex](2x-7)(3x+4)[/tex]
